### Problem Description：

You are given n chips on a number line. The i-th chip is placed at the integer coordinate . Some chips can have equal coordinates.

You can perform each of the two following types of moves any (possibly, zero) number of times on any chip:

• Move the chip i by 2 to the left or 2 to the right for free (i.e. replace the current coordinate  with  or with );
• move the chip i by 1 to the left or 1 to the right and pay one coin for this move (i.e. replace the current coordinate  with  or with ).

Note that it’s allowed to move chips to any integer coordinate, including negative and zero.

Your task is to find the minimum total number of coins required to move all n chips to the same coordinate (i.e. all  should be equal after some sequence of moves).

### Input Specification:

The first line of the input contains one integer n (1 ≤ n ≤ 100) — the number of chips.

The second line of the input contains n integers ,,…, (1 ≤  ≤ 109), where  is the coordinate of the i-th chip.

### Output Specification:

Print one integer — the minimum total number of coins required to move all n chips to the same coordinate.

3
1 2 3

5
2 2 2 3 3

2

### AC代码：

``````#include <bits/stdc++.h>
using namespace std;
#define Up(i,a,b) for(int i = a; i <= b; i++)

int main()
{
ios::sync_with_stdio(false);
int n, odd = 0, even = 0;
cin >> n;
Up(i,1,n)
{
int _;
cin >> _;
(_%2 ? odd++ : even++);  //判断奇偶性，并记录奇偶数的个数
}
cout << min(odd,even) << endl;
return 0;
}`````` 